The oxidation of hydrocarbon (RH) proceeds in the general case according to the following scheme:
Initiation RH → R* H*
Chain development R* O2 → RO2
RO2 RO2 → products.
a) graphically and analytically calculate the rate constant of the initiation reaction from tabular data:
[RH], mol/l 10 8.99 6.08 5.28 3.45 2.25 1.18
τ , s 0 5 10 30 50 70 100
b) Using the temperature dependence of the rate constant
t0C 496 441 394 352 315 283
kspeed 464 245 137 73.7 41.9 22.2
Determine the activation energy graphically.

If you do not open the file - install the RAR archiver. Inside the archive you will find a solution in Word format.