46. The speed of the ordered movement of electrons in a steel wire is 0.5 mm / s, the concentration of conduction electrons is 4 ∙ 1028 m − 3, and the cross-sectional area of the wire is 3 mm2. Determine the current strength. The electron charge is 1.6 ∙ 10−19 C.

Detailed solution. Decorated in Microsoft Word 2003. (Target decided to use formula editor)