102. 1 liter of solution contains 111 g Al2(SO4)3∙18H2O. How many milliliters of such a solution will be required to obtain 0.85 g of Al2O3?

Read the product description. After payment, the system will redirect you to a page with a ready-made solution to problem 102 from the collection: Z. E. Golbreich, E. I. Maslov. Collection of problems and exercises in chemistry: Textbook. manual for chemical technology. specialist. universities - 5th ed., revised. and additional - M.: Higher School, 1997. - 384 p.: ill. The solution is a document formatted in MS Word.
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