Solution of task 108 of Chemistry Book Shimanovich 2003
📂 Chemistry
👤 Михаил_Перович
Product Description
108. Based on the values of the standard heats of formation and absolute standard heats
entropy of the corresponding substances, calculate the G0298 reaction, proceeding according to the equation:
NH3 (g) + HCl (g) = NH4Cl (k)
Can this reaction proceed spontaneously under standard conditions?
Answer: -92.08 kJ
entropy of the corresponding substances, calculate the G0298 reaction, proceeding according to the equation:
NH3 (g) + HCl (g) = NH4Cl (k)
Can this reaction proceed spontaneously under standard conditions?
Answer: -92.08 kJ
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